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Class B : 2 X 105 instr. << /Length 5 0 R /Filter /FlateDecode >> 17 0 obj

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What is the global CPI for each implementation? 4 0 obj << /Type /XRef /Length 70 /Filter /FlateDecode /DecodeParms << /Columns 5 /Predictor 12 >> /W [ 1 3 1 ] /Index [ 12 45 ] /Info 10 0 R /Root 14 0 R /Size 57 /Prev 103597 /ID [<7ddedb40e1bd8c94dbf832faf764b4a3>] >> What is the global CPI for each implementation Find the clock cycles required. Course Hero, Inc. Speedup = (10,000,000 x 2.5 x 5x10-9) / (9,500,000 x 3 x 3.33x10-9 ) = .125 / .095 = 1.32 or 32 % faster after changes. Compilers can have a profound impact on the performance of an application. Given a . stream

rate and CPI of each implementation are given in the following table. Speedup = Old Execution Time = I old x CPI old x Clock cycle old New Execution Time I new x CPI new x Clock Cycle new Speedup = Old Execution Time = I old x CPI … Course Hero is not sponsored or endorsed by any college or university. 12 0 obj   Privacy Introducing Textbook Solutions. *Wc*NM�B߿04�2�. Clockrate CPI ClassA CPI ClassB CPI ClassC CPI Class D 1.5 GHz 2 GHz 1.4.1 [10] <1.4> Given a program with 106 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C and 20% class D, which implemen- tation is faster? endstream P1 with a clock rate of 2.5 GHz and CPIs of 1, 2, 3, and 3, and P2 with a clock rate of 3 GHz and CPIs of 2, 2, 2, and 2.

instr. class B, 50% class C, and 20% class D, which implementation is faster? 9����E� �����gC7 � Assume that for a program, compiler A results in a dynamic instruction count of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a dynamic instruction count of 1.2E9 and an execution time of 1.5 s. Computer Organization and Design MIPS Edition: The Hardware/Software Interface x�c```b``ne`f``aad�0��� }����700����U,v��pQ �``�, Ҝ@� �c�g`��[0�9d��i��3̾����� g�� What's the global CPI? 1.4.2 [51 <1.4> What is the global CPI for each implementation? Class A : 105 instr. Time = No. << /Filter /FlateDecode /Length 2004 >> �f_�ɪz^\#�����t t_ȋ�����9�K駷n�դ��x��!0XAAKa������U�dX��A�W���{�/g��Sb-���p�����A��pS��+��� �P��B�B * U��$+P�l) 4� p�@

  Terms. ��i�^T��$�eB#FY�nj8Q&Qo�����Y���WYf�h��Ld��JPS�N�IV�eU#���]p������ [10 pts] b) What is the global CPI for each implementation? endobj

Clock Rate: 2.0GHZ Class A: 20%, CPI 2 Class B: 30%, CPI 1 Class C: 10%, CPI 3 Class D: 20%, CPI 4 Class E: 20%, CPI 5 I solved a.b but not c .. so I need help- for problem c.. and here are the answer for the a and b . stream stream The instructions can be divided into four classes according to their CPI (class A, B, C, and D). Class C : 5 105 instr. 14 0 obj x�[��������Հ�խ�H���ݵ ��f� ��B>L�Kn���TUW��#͘��.�]]u��ե���g�O���ݶ�iӗ��O�҇�n]zs���� ����n�"-ۼm�§7/��봖��r�"}x} ���7iv�J����_cB��vu�۴l��|��k�uk��2�|r,J�͛J�H�|$c>^���

CPI = (4x50 + 5x10 + 4x20 + 3x8 + 3x2)/100 = 3.6. endstream x�cbd`�g`b``8 "���lcɸ���� R��^"լA�r7��K������7 �b`�$ �J � T{�����:��D�_��h�6�yA��į������� _����ҷ\��_���|�^��0�S@�|�Ny6(Mg+���Vf{����e2�nŏo�R����7�~�orD���I%�3��WE^7���Cfo��摌��,��U�����˺�NNV�Z������hc�G)%��+�-V@�̣U�e�v뀖: 7b�m�-*C�� Y�B>�"( �(1V �'�Mgӱ���Z^MW�U�`��FLl��" �YST���"���7\����X%M��UZ��W�)�J3/p�y5���K_�abayyb�"��B�b�Uy�*�:p�1��8eF �]W~�B �mU��,�Uv.w]�b�#'�|A��hҦ.i�����/��������j���Ze�BF^1*#�����n�1���"��}��w䕸���]�%?H���O��=FSFK�3��Gܺ��������?�}�{^��K�[p��! �b�˯�Y�`��_5��Z��ijd_o*����2�0oE��z(Y�lR��n&�������P�n$�u�d:G�j�!�@��7g��D���D)����\���HF�$�2ϢiG��!�K����؞�:T�(��4�x�a&o9�5����|\��F�S�b(ɮF��u6�h#��q~����8t��9�r[��4U����~�1�D�О�#��ܜ��̹�44� O���5fj�)��� � 3�;%���W�-Ww������S�َ瀘��/�/ے�����x�F&�h ����L�آ߭)W�!o�PWz'w�E�5jã�� H�b���ۅ�_,wyM� ���. a. %PDF-1.3

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a) What is the global CPI for each implementation? 16 0 obj b) Find the clock cycles required in both cases. x��ZKo�8��W�R@b�O��(�ڶ{Xh��{Pl9jK�$7���r(Y���n���=I�����ɗ�������$��]�F�3K6�UB4�G���_ѫo�Ƃ����]��n�x��g������Xf��Q��OT�Y�X�֔����/��~��I"ḏ_A�JFc��L��;Ѷ2��E�(Ye��$Q����*6���4���\���ӵ�����g,2�7#�H��Sb̴&� If the execution, times on the two processors are the same, how much faster is the clock of the, processor running compiler A’s code versus the clock of the processor running, A new compiler is developed that uses only 6.0E8 instructions and has an, average CPI of 1.1. What is the speedup of using this new compiler versus using.

a. - 5th Edition. {D�%( �e�p!����M���̬k��K2z���S��ŒI2��K��L�V�����Ț��i�0�Rf�/Z�u�6�y��}a����q �i�Z����?����7 � 4������#X��~譼:{T��ك�_Z���*ʼp)��|��xAa�ɯ�R���UɻJ�,/��%�!y��/� 8Χ@ A���T�z�^��6 program with 106 instructions divided into classes as follows: 10% class A, 20% class B, 50% class C, and 20% class D, which implementation is faster?

Class D : 2 510 instr. This problem will explore the impact compilers have on execution time. 13 0 obj What is the global CPI for each implementation? endobj 15 0 obj Community College of City University • AST 1020, Copyright © 2020. << /Linearized 1 /L 103936 /H [ 901 174 ] /O 16 /E 75211 /N 4 /T 103596 >>

What's the CPU time?

Find the clock cycles required in both cases. c. Give two options for improving the CPU performance by 25%. compiler A or B on the original processor? Do the calculation on your own, and check the, Speed up of new compiler compared to A = 1.67, Speed up of new compiler compared to B = 2.27, Performance is specific to a particular program, total execution time is a consistent summary of. << /Filter /FlateDecode /S 69 /Length 96 >> 3. %��������� New CPI: 3.0 – Faster CPU implementation: New clock rate = 300 MHz • What is the speedup with the changes? endobj Get step-by-step explanations, verified by experts. %���� CPI/clock rate Total time P1 = (105 + 2 10 5 2 + 5 10 3 + 2 105 3)=(2:5 109) = 10:4 10 4s Total time P2 = (105 52 + 2 105 52 + 5 10 2 + 2 10 2)=(3 109) = 6:66 10 4s Compilers can have a profound impact on the performance of an application. �m�q�7��� �sI�W�u������2G�Chm� << /Contents 17 0 R /MediaBox [ 0 0 612 792 ] /Parent 32 0 R /Resources 25 0 R /Type /Page >> Assume that for a program, compiler A results in a dynamic instruction count, of 1.0E9 and has an execution time of 1.1 s, while compiler B results in a. dynamic instruction count of 1.2E9 and an execution time of 1.5 s. Find the average CPI for each program given that the processor has a clock, Assume the compiled programs run on two different processors. Calculation of CPI (Cycles Per Instruction) For the multi-cycle MIPS Load 5 cycles Store 4 cycles R-type 4 cycles Branch 3 cycles Jump 3 cycles If a program has 50% R-type instructions 10% load instructions 20% store instructions 8% branch instructions 2% jump instructions then what is the CPI? For a limited time, find answers and explanations to over 1.2 million textbook exercises for FREE! endobj [5 pts] 15) Compilers can have a profound impact on the performance of an application on a given processor. endobj << /Pages 32 0 R /Type /Catalog >> For a given architecture performance increases come from: increases in clock rate (without adverse CPI affects), improvements in processor organization that lower CPI, compiler enhancements that lower CPI and/or, : expecting improvement in one aspect of a, machine’s performance to affect the total performance, This textbook can be purchased at www.amazon.com.



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